تحديات برمجيةالتحدي الثاني - حل التمرين الثاني بلغة بايثون

def replace_all(text, find, replacement):

    text_length = len(text)
    find_length = len(find)
    new_string = ''

    i = 0
    while i < text_length:

        if i <= text_length - find_length and text[i: i + find_length] == find:
            new_string += replacement
            i += find_length

        else:
            new_string += text[i]
            i += 1

    return new_string


text = "I like cats. I have one cat."
find = "cat"
replacement = "dog"
newText = replace_all(text, find, replacement)

print("Before:", text)
print("After: ", newText)

Before: I like cats. I have one cat.
After:  I like dogs. I have one dog.