تحديات برمجيةالتحدي الخامس - حل التمرين الثاني بلغة C

#include <stdio.h>

void main() {
    
    int n;
    
    do {
        printf("Enter an odd number as the number of lines: ");
        scanf("%d", &n);
    }
    while( n<=0 || n%2==0 );
        
    for( int i=1; i<=n; i++ )
    {
        for( int j=1; j<=n; j++ )
        {
            if ( (i <= n/2 + 1 && j <= n/2 + 1) || (i > n/2 && j > n/2) )
            {
                printf("*");
            }
            else
            {
                printf(" ");
            }
        }
        printf("\n");
    }
    
}

#include <stdio.h>

void main() {
    
    int n;
    
    do {
        printf("Enter an odd number as the number of lines: ");
        scanf("%d", &n);
    }
    while( n <= 0 || n % 2 == 0 );
        
    for (int i = 1; i <= n; i++)
    {
        if (i <= n / 2)
        {
            for (int j = 1; j <= n / 2 + 1; j++)
            {
                printf("*");
            }
        }
        else if (i == n / 2 + 1)
        {
            for (int j = 1; j <= n; j++)
            {
                printf("*");
            }
        }
        else
        {
            for (int k = 1; k <= n / 2; k++)
            {
                printf(" ");
            }
            for (int j = 1; j <= n / 2 + 1; j++)
            {
                printf("*");
            }
        }
            
        printf("\n");
    }
    
}

Enter an odd number as the number of lines: 9
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    *****
    *****
    *****
    *****