تحديات برمجيةالتحدي الثالث - حل التمرين الأول بلغة بايثون

n = 0

while n <= 0 or n % 2 == 0:
    n = int(input("Enter the number of lines: "))

for i in range(1, n + 1):

    if i <= n / 2:
        print(' ' * (int(n / 2) - i + 1), end='')
        print('*', end='')
        print('*' * ((i * 2) - 2), end='')

    else:
        print(' ' * (i - int(n / 2) - 1), end='')
        print('*', end='')
        print('*' * ((n*2)-(i*2)), end='')

    print()

n = 0

while n <= 0 or n % 2 == 0:
    n = int(input("Enter the number of lines: "))

for i in range(1, n + 1):

    if i <= n / 2:

        for k in range(1, int(n / 2) - i + 2):
            print(' ', end='')

        print('*', end='')

        for j in range(1, (i * 2) - 1):
            print('*', end='')

    else:

        for k in range(1, i - int(n / 2)):
            print(' ', end='')

        print('*', end='')

        for j in range(1, (n * 2) - (i * 2) + 1):
            print('*', end='')

    print()

n = 0

while n <= 0 or n % 2 == 0:
    n = int(input("Enter the number of lines: "))

for i in range(1, int(n / 2) + 2):
    print(' ' * (int(n / 2) - i + 1), end='')
    print('*', end='')
    print('*' * ((i * 2) - 2))

for i in range(1, int(n / 2) + 1):
    print(' ' * i, end='')
    print('*' * ((int(n / 2) * 2) - (i * 2) + 1))

n = 0

while n <= 0 or n % 2 == 0:
    n = int(input("Enter the number of lines: "))

for i in range(1, int(n / 2) + 2):

    for k in range(1, int(n / 2) - i + 2):
        print(' ', end='')

    print('*', end='')

    for j in range(1, (i * 2) - 1):
        print('*', end='')

    print()

for i in range(1, int(n / 2) + 1):

    for k in range(1, i + 1):
        print(' ', end='')

    for j in range(1, (int(n / 2) * 2) - (i * 2) + 2):
        print('*', end='')

    print()

Enter the number of lines: 9
    *
   ***
  *****
 *******
*********
 *******
  *****
   ***
    *