تحديات برمجيةالتحدي الثاني - حل التمرين الثاني بلغة بايثون

n = 0

while n <= 0:
    n = int(input("Enter the number of lines: "))

for i in range(1, n+1):
    print(' ' * (n-i), end='')
    print('*', end='')
    print('*' * (i*2-2))

n = 0

while n <= 0:
    n = int(input("Enter the number of lines: "))

for i in range(1, n+1):

    for k in range(1, n+1-i):
        print(' ', end='')

    print('*', end='')

    for j in range(1, (i*2)-1):
        print('*', end='')

    print()

n = 0

while n <= 0:
    n = int(input("Enter the number of lines: "))

i = 1
while i <= n:

    k = 1
    while k <= n-i:
        print(' ', end='')
        k += 1

    print('*', end='')

    j = 1
    while j < (i*2)-1:
        print('*', end='')
        j += 1

    print()
    i += 1

Enter the number of lines: 5
    *
   ***
  *****
 *******
*********