تحديات برمجيةالتحدي الثاني - حل التمرين الأول بلغة بايثون

n = 0
m = 0

while n <= 0:
    n = int(input("Enter the number of lines: "))

while m <= 0:
    m = int(input("Enter the number of columns: "))

for i in range(1, n+1):
    print(' ' * (i-1), end='')
    print('*' * m)

n = 0
m = 0

while n <= 0:
    n = int(input("Enter the number of lines: "))

while m <= 0:
    m = int(input("Enter the number of columns: "))

for i in range(1, n+1):

    for k in range(1, i):
        print(' ', end='')

    for j in range(1, m+1):
        print('*', end='')

    print()

n = 0
m = 0

while n <= 0:
    n = int(input("Enter the number of lines: "))

while m <= 0:
    m = int(input("Enter the number of columns: "))

i = 1
while i <= n:

    k = 1
    while k < i:
        print(' ', end='')
        k += 1

    j = 1
    while j <= m:
        print('*', end='')
        j += 1

    print()
    i += 1

Enter the number of lines: 5
Enter the number of columns: 10
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