تحديات برمجيةالتحدي الخامس - حل التمرين الخامس بلغة بايثون

rows = 3
cols = 3

matrix = [[0] * cols for i in range(rows)]

sum_on_diagonals = 0
sum_above_diagonals = 0
sum_under_diagonals = 0

for i in range(rows):
    for j in range(cols):
        matrix[i][j] = int(input("Enter matrix[" + str(i) + "][" + str(j) + "]: "))

for i in range(rows):
    for j in range(cols):

        if j > i:
            sum_above_diagonals += matrix[i][j]

        elif j < i:
            sum_under_diagonals += matrix[i][j]

        else:
            sum_on_diagonals += matrix[i][j]

print('\nSum of elements above diagonals:', sum_above_diagonals)
print('Sum of elements under diagonals:', sum_under_diagonals)
print('Sum of elements on diagonals:', sum_on_diagonals)