تحديات برمجيةالتحدي الرابع - حل التمرين الخامس بلغة بايثون

rows = 3
cols = 3

matrix = [[0] * cols for i in range(rows)]
array = [0] * rows * cols

for i in range(rows):
    for j in range(cols):
        matrix[i][j] = int(input("Enter matrix[" + str(i) + "][" + str(j) + "]: "))

print("\nMatrix values")
for i in range(rows):
    for j in range(cols):
        print(matrix[i][j], end=" ")
    print()

for i in range(rows):
    for j in range(cols):
        array[j + (i * cols)] = matrix[i][j]

print("\nArray values")
for i in range(len(array)):
    print(array[i], end=" ")