تحديات برمجيةالتحدي الثاني - حل التمرين الثالث بلغة بايثون

n = 0
while n <= 0:
    n = int(input('Enter the length of A and B: '))

A = [0] * n
B = [0] * n
C = [0] * (n * 2)

for i in range(0, n):
    A[i] = int(input('Enter A[' + str(i) + ']: '))

for i in range(0, n):
    B[i] = int(input('Enter B[' + str(i) + ']: '))

for i in range(0, n):
    C[i] = A[i]

for i in range(0, n):
    C[n + i] = B[i]

print('\nC contains:', end=' ')

for i in range(0, n * 2):
    print(C[i], end=' ')