تحديات برمجيةالتحدي الأول - حل التمرين الرابع بلغة بايثون

n = 0
while n <= 0:
    n = int(input('Enter arr length: '))

arr = [0] * n

for i in range(0, n):
    arr[i] = int(input('Enter arr[' + str(i) + ']: '))

print('\nCurrent order')

for i in range(0, n):
    print(arr[i], end=' ')

for i in range(0, n - 1):
    for j in range(i + 1, n):
        if arr[j] < arr[i]:
            temp = arr[i]
            arr[i] = arr[j]
            arr[j] = temp

print('\n\nAfter ascending order')

for i in range(0, n):
    print(arr[i], end=' ')