تحديات برمجيةالتحدي الثاني - حل التمرين الرابع بلغة بايثون

S1 = input("Enter S1: ")
S2 = input("Enter S2: ")
S3 = input("Enter S3: ")
S4 = ""

print("---------------------------------------")

# Part 1
print("The concatenation of S1 and S2 is equal S3?", S3 == S1 + S2)

# Part 2
print("S1 is part of S2 or S1=S2?", S2.find(S1) != -1)

# Part 3
if len(S1) > len(S2):
    S4 = S2 + S1

# Part 4
if len(S2) > len(S1):
    S4 = S1 + S2

# Part 5
print("S2 is part of the second half of S1?", S1.find(S2, int(len(S1) / 2)) != -1)

# Part 6
print("The first half characters of S1 are:", S1[0: int(len(S1) / 2)])