تحديات برمجيةالتحدي الثاني - حل التمرين الثالث بلغة C

#include <stdio.h>

void main() {
    
    int a, b, c, minimum;
    
    printf("Enter a: ");
    scanf("%d", &a);
    
    printf("Enter b: ");
    scanf("%d", &b);
    
    printf("Enter c: ");
    scanf("%d", &c);
    
    minimum = (a < b)? a: b;
    minimum = (minimum < c)? minimum: c;
        
    printf("The min number is: %d", minimum);

}

#include <stdio.h>

void main() {
    
    int a, b, c, minimum;
    
    printf("Enter a: ");
    scanf("%d", &a);
    
    printf("Enter b: ");
    scanf("%d", &b);
    
    printf("Enter c: ");
    scanf("%d", &c);
    
    if (a < b && a < c)
    {
        minimum = a;
    }
    else if (b < a && b < c)
    {
        minimum = b;
    }
    else
    {
        minimum = c;
    }
        
    printf("The min number is: %d", minimum);
    
}

#include <stdio.h>

void main() {
    
    int a, b, c, minimum;
    
    printf("Enter a: ");
    scanf("%d", &a);
    
    printf("Enter b: ");
    scanf("%d", &b);
    
    printf("Enter c: ");
    scanf("%d", &c);
    
    if (a < b && a < c)
    {
        minimum = a;
    }
    else
    {
        minimum = b;
    }
        
    if (minimum > c)
    {
        minimum = c;
    }
        
    printf("The min number is: %d", minimum);
    
}

Enter a: 2
Enter b: 7
Enter c: 5
The min number is: 2