تحديات برمجيةالتحدي السابع - حل التمرين الخامس بلغة بايثون

n = 0

while n <= 0 or n % 2 == 0:
    n = int(input("Enter and odd number as the number of lines: "))

for i in range(1, n + 1):

    for j in range(1, n + 1):

        if (i == 1 or i == int(n / 2) or i == int(n / 2) + 2 or i == n or
            j == 1 or j == int(n / 2) or j == int(n / 2) + 2 or j == n)\
                and j != int(n / 2) + 1 and i != int(n / 2) + 1:
            print('*', end='')

        else:
            print(' ', end='')

    print()

Enter an odd number as the number of lines: 11
***** *****
*   * *   *
*   * *   *
*   * *   *
***** *****
           
***** *****
*   * *   *
*   * *   *
*   * *   *
***** *****