تحديات برمجيةالتحدي السابع - حل التمرين الخامس بلغة C++

#include <iostream>

int main() {

    int n;

    do {
        std::cout << "Enter an odd number as the number of lines: ";
        std::cin >> n;
    }
    while (n <= 0 || n % 2 == 0);

    for (int i = 1; i <= n; i++)
    {
        for (int j = 1; j <= n; j++)
        {
            if ((i == 1 || i == n / 2 || i == n / 2 + 2 || i == n ||
                 j == 1 || j == n / 2 || j == n / 2 + 2 || j == n)
                && j != n / 2 + 1 && i != n / 2 + 1)
            {
                std::cout << "*";
            }
            else
            {
                std::cout << " ";
            }
        }
        std::cout << "\n";
    }

    char end; std::cin >> end;
    return 0;

}

Enter an odd number as the number of lines: 11
***** *****
*   * *   *
*   * *   *
*   * *   *
***** *****
           
***** *****
*   * *   *
*   * *   *
*   * *   *
***** *****