تحديات برمجيةالتحدي السابع - حل التمرين الخامس بلغة C

#include <stdio.h>

void main() {

    int n;

    do {
        printf("Enter an odd number as the number of lines: ");
        scanf("%d", &n);
    }
    while (n <= 0 || n % 2 == 0);

    for (int i = 1; i <= n; i++)
    {
        for (int j = 1; j <= n; j++)
        {
            if ((i == 1 || i == n / 2 || i == n / 2 + 2 || i == n ||
                 j == 1 || j == n / 2 || j == n / 2 + 2 || j == n)
                && j != n /2 + 1 && i != n /2 + 1)
            {
                printf("*");
            }
            else
            {
                printf(" ");
            }
        }
        printf("\n");
    }

}

Enter an odd number as the number of lines: 11
***** *****
*   * *   *
*   * *   *
*   * *   *
***** *****
           
***** *****
*   * *   *
*   * *   *
*   * *   *
***** *****