تحديات برمجيةالتحدي السابع - حل التمرين الرابع بلغة بايثون

n = 0

while n <= 0 or n % 2 == 0:
    n = int(input("Enter and odd number as the number of lines: "))

for i in range(1, n + 1):

    for j in range(1, n + 1):

        if (i == 1 or i == n or j == int(n / 2) or j == int(n / 2) + 2 or i == j or j == n - i + 1)\
                and i != int(n / 2) + 1 and j != int(n / 2) + 1:
            print('*', end='')

        else:
            print(' ', end='')

    print()

Enter an odd number as the number of lines: 11
***** *****
 *  * *  * 
  * * * *  
   ** **   
    * *    
           
    * *    
   ** **   
  * * * *  
 *  * *  * 
***** *****