تحديات برمجيةالتحدي السادس - حل التمرين الخامس بلغة بايثون

n = 0

while n <= 0 or n % 2 == 0:
    n = int(input("Enter and odd number as the number of lines: "))

for i in range(1, n + 1):

    for j in range(1, n + 1):

        if i == int(n / 2) + 1 or j == int(n / 2) + 1:
            print(' ', end='')

        else:
            print('*', end='')

    print()

Enter an odd number as the number of lines: 9
**** ****
**** ****
**** ****
**** ****
         
**** ****
**** ****
**** ****
**** ****