تحديات برمجيةالتحدي السادس - حل التمرين الرابع بلغة بايثون

n = 0

while n <= 0 or n % 2 == 0:
    n = int(input("Enter and odd number as the number of lines: "))

for i in range(1, n + 1):

    for j in range(1, n + 1):

        if (i <= n / 2 + 1 and i <= j <= n - i + 1 or i > n / 2 - 1 and i >= j > n - i) and j != int(n / 2) + 1:
            print('*', end='')

        else:
            print(' ', end='')

    print()

Enter an odd number as the number of lines: 9
**** ****
 *** *** 
  ** **  
   * *   
         
   * *   
  ** **  
 *** *** 
**** ****