تحديات برمجيةالتحدي الخامس - حل التمرين الأول بلغة بايثون

n = 0

while n <= 0 or n % 2 == 0:
    n = int(input("Enter and odd number as the number of lines: "))

for i in range(1, n + 1):

    for j in range(1, n + 1):

        if i <= int(n / 2) and j <= int(n / 2) or i > int(n / 2) + 1 and j > int(n / 2) + 1:
            print(' ', end='')

        else:
            print('*', end='')

    print()

n = 0

while n <= 0 or n % 2 == 0:
    n = int(input("Enter and odd number as the number of lines: "))

for i in range(1, n + 1):

    if i <= n / 2:
        print(' ' * int(n / 2), end='')
        print('*' * (int(n / 2) + 1), end='')

    elif i == int(n / 2) + 1:
        print('*' * n, end='')

    else:
        print('*' * (int(n / 2) + 1), end='')

    print()

Enter an odd number as the number of lines: 9
    *****
    *****
    *****
    *****
*********
*****    
*****    
*****    
*****