تحديات برمجيةالتحدي الرابع - حل التمرين الرابع بلغة بايثون

n = 0

while n <= 0:
    n = int(input("Enter the number of lines: "))

if n % 2 == 0:
    n += 1

for i in range(1, n + 1):

    for j in range(1, n + 1):

        if i == 1 or i == n or j == 1 or j == n or i == j or j == n - i + 1:
            print('*', end='')

        else:
            print(' ', end='')

    print()

n = 0

while n <= 0:
    n = int(input("Enter the number of lines: "))

if n % 2 == 0:
    n += 1

i = 1
while i <= n:

    j = 1
    while j <= n:

        if i == 1 or i == n or j == 1 or j == n or i == j or j == n - i + 1:
            print('*', end='')

        else:
            print(' ', end='')

        j += 1

    print()
    i += 1

Enter the number of lines: 11
***********
**       **
* *     * *
*  *   *  *
*   * *   *
*    *    *
*   * *   *
*  *   *  *
* *     * *
**       **
***********