تحديات برمجيةالتحدي الثاني - حل التمرين الخامس بلغة C

#include<stdio.h>

void main() {
    
    int n;
    
    do {
        printf("Enter the number of lines: ");
        scanf("%d", &n);
    }
    while( n<=0 || n%2==0 );
    
    for( int i=1; i<=n; i++ )
    {
        if( i<=n/2 )
        {
            for (int k=1; k<(n/2)-i+2; k++)
            {
                printf(" ");
            }
            for (int j=1; j<=i; j++)
            {
                printf("*");
            }
        }
        else
        {
            for (int k=1; k<i-(n/2); k++)
            {
                printf(" ");
            }
            for (int j=1; j<n-i+2; j++)
            {
                printf("*");
            }
        }
        printf("\n");
    }
    
}

#include<stdio.h>

void main() {
    
    int n;
    
    do {
        printf("Enter the number of lines: ");
        scanf("%d", &n);
    }
    while( n<=0 || n%2==0 );
    
    for (int i=1; i<(n/2)+2; i++)
    {
        for (int k=1; k<(n/2)-i+2; k++)
        {
            printf(" ");
        }
        for (int j=1; j<=i; j++)
        {
            printf("*");
        }
        printf("\n");
    }
    
    for (int i=1; i<=n/2; i++)
    {
        for (int k=1; k<=i; k++)
        {
            printf(" ");
        }
        for (int j=1; j<(n/2)+2-i; j++)
        {
            printf("*");
        }
        printf("\n");    
    }
    
}

Enter the number of lines: 5
  *
 **
***
 **
  *