تحديات برمجيةالتحدي الثاني - حل التمرين الثالث بلغة بايثون

n = 0

while n <= 0:
    n = int(input("Enter the number of lines: "))

for i in range(1, n+1):
    print(' ' * (i-1), end='')
    print('*', end='')
    print('*' * ((n*2)-(i*2)))

n = 0

while n <= 0:
    n = int(input("Enter the number of lines: "))

for i in range(1, n+1):

    for k in range(1, i):
        print(' ', end='')

    print('*', end='')

    for j in range(1, (n*2) - (i*2) + 1):
        print('*', end='')

    print()

n = 0

while n <= 0:
    n = int(input("Enter the number of lines: "))

i = n
while i >= 1:

    k = 1
    while k <= n-i:
        print(' ', end='')
        k += 1

    print('*', end='')

    j = 1
    while j < (i*2)-1:
        print('*', end='')
        j += 1

    print()
    i -= 1

Enter the number of lines: 5
*********
 *******
  *****
   ***
    *