تحديات برمجيةالتحدي الأول - حل التمرين الثالث بلغة بايثون

n = 0
while n <= 0:
    n = int(input("Enter the number of lines: "))

for i in range(1, n+1):
    print('*' * (n-i+1))

n = 0
while n <= 0:
    n = int(input("Enter the number of lines: "))

for i in range(1, n+1):

    for j in range(1, n+2-i):
        print('*', end='')

    print()

n = 0
while n <= 0:
    n = int(input("Enter the number of lines: "))

i = 1
while i <= n:

    j = 1
    while j <= n+1-i:
        print('*', end='')
        j += 1

    print()
    i += 1

Enter the number of lines: 5
*****
****
***
**
*