تحديات برمجيةالتحدي الأول - حل التمرين الثاني بلغة بايثون

n = 0
while n <= 0:
    n = int(input("Enter the number of lines: "))

for i in range(1, n+1):
    print(' ' * (n - i), end='')
    print('*' * i)

n = 0
while n <= 0:
    n = int(input("Enter the number of lines: "))

for i in range(1, n+1):

    for k in range(1, n+1-i):
        print(' ', end='')

    for j in range(1, i+1):
        print('*', end='')

    print()

n = 0
while n <= 0:
    n = int(input("Enter the number of lines: "))

i = 1
while i <= n:

    k = 1
    while k <= n-i:
        print(' ', end='')
        k += 1

    j = 1
    while j <= i:
        print('*', end='')
        j += 1

    print()
    i += 1

Enter the number of lines: 5
    *
   **
  ***
 ****
*****