تحديات برمجيةالتحدي الخامس - حل التمرين الثاني بلغة بايثون

matrix = [
    [5, 2, 3],
    [4, 5, 6],
    [5, 8, 9]
]

found = 0

x = int(input("Enter a number: "))

for i in range(len(matrix)):
    for j in range(len(matrix[i])):
        if matrix[i][j] == x:
            found += 1

if found == 0:
    print("'" + str(x) + "' is not found")
else:
    print("'" + str(x) + "' is found " + str(found) + " time(s)")