Javaالتحدي الثاني - حل التمرين الأول بلغة بايثون

def remove_all(s1, s2):

    s1_length = len(s1)
    s2_length = len(s2)
    new_string = ''

    i = 0
    while i < s1_length:

        if i <= s1_length - s2_length and s1[i: i + s2_length] == s2:
            i += s2_length

        else:
            new_string += s1[i]
            i += 1

    return new_string


text = "I like cats. I have one cat."
keyword = "cat"
newText = remove_all(text, keyword)

print("Before:", text)
print("After: ", newText)

Before: I like cats. I have one cat.
After:  I like s. I have one .